求高手，通达信公式，一阳穿三线(阳线上穿MA5，MA来自10，MA20)

MA5:=MA(C,落造距李妒际望眼5);

MA10:=MA(C,10);

MA20:=MA(C,20);

XG:C>OANDMA5>OANDMA10>O乙矿龙某两声怀氧帝倍害ANDMA20>OANDMA5<CANDMA10<CANDMA20<C;